Kinematics problem from a competition: Will the 2 sliding boxes collide?

AI Thread Summary
The discussion centers on a kinematics problem involving two sliding boxes and whether they will collide. The first box travels a distance of s1 = u²/(2μg), while the second box travels s2 = 4s1, leading to a total distance of s1 + s2 = 5s1. For a collision to occur, the condition s1 + s2 must be greater than or equal to S, resulting in the requirement u ≥ √(2μgs/5). This derived condition is not included in the provided multiple-choice options, indicating a potential oversight in the problem's construction. The conversation highlights the importance of quality control in exam questions.
Jim Alexandridis
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Homework Statement
two small boxes of rectangular parallelepiped shape are launched simultaneously against each other, with velocities of meters 𝑢1=𝑢 and 𝑢2=2𝑢, from positions A and B of a straight and horizontal trajectory 𝑂𝑥 lying in a plane. The distance between them is 𝛢𝛣=𝑠 and the coefficient of friction between each body and the surface is μ. Boxes will collide if:
a)u≥2√(μgs)/3
b)u≥1√(μgs)/3
c)u≥2√(μgs)/5
d)u≥3√(μgs)/5

This problem was on an greek physics competition on 10th grade and there is a disagreement about the answer, so i would like your opinion depending on my answer
Relevant Equations
Kinematics:
V=v0+at
Dx=v0t+1/2at²
Smax=v²/2a
The distance covered by the first box is :s1max=v²/2|a|=v²/2μg where a=-μg by second newtons law
Similarly S2max=(2v)²/2|a|=4v²/2μg
It gas to be s1max+s2max≥S => v²/2a +4v²/2a ≥s => 5v²≥2aS =>v²≥ 2μgS/5=> v≥√(2μgs/5)
But this is in the possible solution, am I wrong somewhere? I appreciate your help
 
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Hi @Jim Alexandridis and welcome to PF.

The first box travels distance ##s_1=\dfrac{u^2}{2\mu g}##
The second box travels distance ##s_2=\dfrac{(2u)^2}{2\mu g}=\dfrac{4u^2}{2\mu g}=4s_1.##
The two boxes together travel distance ##s_1+s_2=5s_1=\dfrac{5u^2}{2\mu g}##
So what must be true for a collision to take place?

Sometimes multiple choice problems are not very well constructed.
 
kuruman said:
Hi @Jim Alexandridis and welcome to PF.

The first box travels distance ##s_1=\dfrac{u^2}{2\mu g}##
The second box travels distance ##s_2=\dfrac{(2u)^2}{2\mu g}=\dfrac{4u^2}{2\mu g}=4s_1.##
The two boxes together travel distance ##s_1+s_2=5s_1=\dfrac{5u^2}{2\mu g}##
So what must be true for a collision to take place?

Sometimes multiple choice problems are not very well constructed.
Isn’t that the same as the OP did in post #1?
 
haruspex said:
Isn’t that the same as the OP did in post #1?
Yes. It's reassurance to a new user that when you're right, you're right.
 
I believe that for the collision to happen it has to be :

##S_{1}+S_{2}\ge S##
 
Jim Alexandridis said:
I believe that for the collision to happen it has to be :

##S_{1}+S_{2}\ge S##
That is correct. As you already posted, this condition leads to $$u \geq \sqrt{\frac{2\mu~g~s}{5}}$$which is not one of the options (a) - (d). What you can do with this information is up to you. It ranges from doing nothing to bringing it to the attention of someone who is in a position to improve the quality control of exams like this.
 
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kuruman said:
That is correct. As you already posted, this condition leads to $$u \geq \sqrt{\frac{2\mu~g~s}{5}}$$which is not one of the options (a) - (d). What you can do with this information is up to you. It ranges from doing nothing to bringing it to the attention of someone who is in a position to improve the quality control of exams like this.
It might be a "copy/paste" issue. For example, in some other forum, I've just posted in LaTeX:
1712846272189.png

but after "edit and save" it has been converted to this:

1712846529653.png
 
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