Kinematics - projectile motion - time to maximum height?

AI Thread Summary
The discussion focuses on calculating the time it takes for a water drop from a fire hose, aimed straight up, to reach its maximum height. The initial velocity is given as 10 m/s, with a final velocity of 0 m/s at the apex, and acceleration due to gravity is -9.8 m/s². Using the kinematic equation Vfy = Viy + Ay*t, the time calculated is approximately 1.02 seconds, which rounds to 1.0 seconds for significant figures. It is clarified that this time represents the total time for the upward motion, and thus, the time to reach maximum height is half of that, approximately 0.51 seconds. The discussion also touches on the nature of projectile motion and the concept of parabolic trajectories.
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Kinematics -- projectile motion -- time to maximum height?

Homework Statement


The nozzle of a fire hose discharges water at a speed of 10 m/s. The nozzle is aimed straight up. How long does it take for a water drop to reach its maximum height?
Start with translating the question:
vi= 10 m/s
vf= 0 m/s
t=? s
a= -9.8 m/s^2
delta−x= ?

Homework Equations





The Attempt at a Solution



OK, so I'm assuming that solving this takes 2 steps. One entails finding the maximum height, then using a kinematic formula to find time. Is that logic sound?
 
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What are the relevant equations?

ehild
 
I tried this:
Vfy=Viy+Ay*t
0 m/s=10 m/s-9.8 m/s^2*t
-10 m/s=-9.8 m/s^2 *t
t=10 m/s / -9.8 m/s^2
t=1.02 s
 
It is correct. You see, the maximum height was not needed. ehild
 
1.02 s is not an option for this multiple choice problem, the closest is 1.0 s. Is that likely the answer then?

Edit: The question asks how long it takes to reach maximum height, so because it is a parabola, it stands to reason that 1.02s/2=0.51s is how long it takes to reach the maximum height. Right?
 
The data in the problem are given with two significant digits. Round of your result to t=1.0 s. .

What is parabola?

When does a body projected straight upward reach maximum height? What is its velocity at the apex?
What is the maximum height?

What would be the velocity at t=0.5 s? Would the water drop move upward or downward then? Does it reach the maximum height at t=0.5 s?

ehild
 
I don't know. I remember someone in class saying that projectile motion was a parabola...

t=1.0 s means what? The time it takes for the motion to finish? or the time at which the water reaches its maximum height?
 
The motion is not parabola. A graph of a function can be parabola.

You applied the equation Vfy=Viy+Ay*t. What do the letters mean? You substituted Vfy=0. If you throw up a pebble, will it reach the ground with zero velocity? Where is the velocity zero?
Just throw up something and see...

ehild
 
kenji1992 said:
I don't know. I remember someone in class saying that projectile motion was a parabola...

The problem statement says "The nozzle is aimed straight up".
 
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