Kinematics Question -- 2 Runners Racing Each Other

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Dave runs at a constant speed of 20 m/s and accelerates after 2 seconds to catch up with Andrew, who maintains a constant speed. The calculation shows Dave travels 812.5 meters in 25 seconds, but it fails to account for the distance Andrew covers during the initial 2 seconds. The discussion highlights the need to include Andrew's distance in the overall calculations to determine his velocity accurately. The final conclusion points out that while Dave's distance calculation is correct, it overlooks the crucial initial distance Andrew gains. Accurate results require considering both runners' movements during the entire timeframe.
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Homework Statement



Dave and Andrew are racing. Dave running at a constant speed of 20m/s is passed by Andrew. 2.0s after Andrew passes, Dave accelerates at 1.0m/s^2 until he catches up with Andrew 25s later. What is Andrew's velocity (he does not accelerate)?

Homework Equations



Kinematics Formulas.

The Attempt at a Solution


d=vit+1/2at^2
=(20)(25)+1/2(1)(25)^2
=812.5

Dave travels 812.5m.
v=d/t
=(812.5)(25+2)
=30.7m/s

I'm not sure if the way I did it was correct. Can someone please tell me how to do it. If you think I'm right though can you please tell me. Thanks!
 
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You seem to have forgotten that 2 seconds went by before Dave accelerated. during these two seconds both runners moved.
 
Usain Bolt runs at 12.4m/s but can only sustain that speed for 20 or 30m. So there is something unrealistic about the numbers you are given.

With that said, looks like you calculated "d" right but missing the distance that Andrew is ahead after the first 2 seconds.
 
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