Kinematics/Vectors Homework: Initial Velocity, Acceleration, Speed & Direction

  • Thread starter Thread starter bikerboi92
  • Start date Start date
  • Tags Tags
    Kinematics Vectors
AI Thread Summary
The discussion revolves around calculating the final speed and direction of a particle with given initial velocities and accelerations. The particle has an initial horizontal velocity of 2.6 m/s and an upward velocity of 3.5 m/s, with horizontal acceleration of 1.3 m/s² and downward acceleration of 1.2 m/s². Participants emphasize treating horizontal and vertical components separately and applying the kinematic equation for final velocity. After calculating the components, the direction of the resultant velocity can be determined using trigonometric principles. The original poster successfully solved the problem and confirmed they obtained the correct answer.
bikerboi92
Messages
8
Reaction score
0

Homework Statement



A particle has an initial horizontal velocity of 2.6 m/s and an initial upward velocity of 3.5 m/s. It is then given a horizontal acceleration of 1.3 m/s^2 and a downward acceleration of 1.2 m/s^2.

What is its speed after 2.2 s?

What is the direction of its velocity at this time with respect to the horizontal (answer between -180º and +180º)


Homework Equations



all kinematic equations


The Attempt at a Solution



i'm lost on this one
 
Physics news on Phys.org
Welcome to PF.

Acceleration is a vector. Velocity is a vector.

You can treat the horizontal and vertical components separately.

You know for instance that Final Velocity is equal to Initial velocity + acceleration times time. Vf = Vi + a*t

Once you determine your components of the resulting Velocity ... combine ... you're done.
 
You are going to end up with 2 final velocities, one in the x and one in the y.

So to find the direction from the positive x axis, take triangles into consideration. You'll have an x component and a y component so you can easily solve for the direction with respect to the horizontal.
 
thanks, i solved and got the right answer
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top