Kinetic and Gravitational Energy Related Questions

AI Thread Summary
A 6.5 kg ball launched upwards at 21 m/s will reach a height of 22.5 meters if all its kinetic energy is converted to gravitational potential energy. The calculations show that the ball's kinetic energy is 1433.25 J, which, when divided by the product of its mass and gravitational acceleration, yields the height. In another scenario, a 5 kg watermelon falling from a 43.0 m high balcony will hit the ground at a speed of 29.03 m/s if all its gravitational potential energy is converted to kinetic energy. The gravitational potential energy for the watermelon is calculated to be 2107 J, leading to the final speed using the appropriate formula. Both calculations are confirmed to be correct.
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1. A 6.5 kg ball is launched upwards from the ground with a speed of 21 m/s. If all of the ball's kinetic energy is converted to gravitational potential energy, how high will the ball go?

Given:

m = 6.5kg
v = 21m/s
Ek = 1433.25 J
g = 9.8 N/kg [down]

Required:

h =?

Solution:

h = Ek/mg
h = 1433.25 J / (6.5kg)(9.8 N/kg)
h = 22.5m

If all of the ball's kinetic energy is converted to gravitational potential, the ball will go 22.5m high.


2. A 5 kg watermelon is placed on the edge of a balcony 43.0 m high. If all of the gravitational potential energy is converted into kinetic energy after the box is pushed off the balcony, how fast will the watermelon be moving when it hits the ground?

Given:

m = 5 kg
h = 43.0 m
g = 9.8 N/kg [down]
EG = 2107 J

Required:

v =?

Solution:

v = square root 2 EG/ m
v = 2(2107 J)/5 kg
v = 29.03m/s

If all of the gravitational potential energy is converted into kinetic energy after the box is pushed off the balcony, the watermelon would be moving at a speed of 29.03m/s.

So, are my calculations correct?
 
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