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## Main Question or Discussion Point

Okay, so the situation is a hydro-electric plant, assumed to have a vertical inlet pipe, of (s) metres high, and a opening to the turbine of (d) metres in diameter. The water is assumed to be stationary before it begins falling down the pipe (s) metres. So, I have the speed of the water when it reaches the bottom, beng the potential verses the kinetic gained, hence;

v = [tex]\sqrt{}(2gh)[/tex] (h being s, sorry lol..)

Anyways I alos have the mass of water entering the pipe in 1 second, from which I assume I can work out the power output of the generato, assuming that the turbine is direclty under the inlet opening etc. Now, a watt is a joule/sec, hence finding the mass entering the turbine in one second should help me obatin P, (= W/t). So;

the mass of water in 1 second = 250[tex]\pi[/tex]d^2 ([tex]\sqrt{}(2gh))[/tex] [in kilograms].

The question I pose, is it legitimae, or, rather, correct, to try and find the Power output by first using F=ma, to find the force exerted by the mass of water, then use W = fs, for the work that can be done by this, and then to use P = w/t? Or is the a way to directly convert from Ke, to electrical enegery, or power, in watts?

Thanks.

v = [tex]\sqrt{}(2gh)[/tex] (h being s, sorry lol..)

Anyways I alos have the mass of water entering the pipe in 1 second, from which I assume I can work out the power output of the generato, assuming that the turbine is direclty under the inlet opening etc. Now, a watt is a joule/sec, hence finding the mass entering the turbine in one second should help me obatin P, (= W/t). So;

the mass of water in 1 second = 250[tex]\pi[/tex]d^2 ([tex]\sqrt{}(2gh))[/tex] [in kilograms].

The question I pose, is it legitimae, or, rather, correct, to try and find the Power output by first using F=ma, to find the force exerted by the mass of water, then use W = fs, for the work that can be done by this, and then to use P = w/t? Or is the a way to directly convert from Ke, to electrical enegery, or power, in watts?

Thanks.