What carries the energy in an electric current?

AI Thread Summary
Electric current is often compared to water flow, with voltage analogous to water pressure and current to the flow rate. The energy in an electric current primarily comes from the electric field, which pushes electrons through a conductor, rather than their kinetic energy, which is negligible in practical circuits. An increase in voltage does not significantly increase the drift speed of electrons; instead, it enhances the electric field's force on them. The analogy of water flow is useful, but it is important to recognize that the kinetic energy of electrons is not a significant factor in energy transfer in typical electrical circuits. Understanding these concepts clarifies the nature of energy transfer in electrical systems.
  • #51
DrZoidberg said:
Imagine you put a table inside a big solenoid. On that table you place a magnet and put a heavy object on top to make sure the magnet can only move slowly.
Then you turn on the solenoid so that the magnet moves slowly over the table at a !constant! speed.
Because of friction, the table and the magnet will become warmer. You could claim that the kinetic energy of the magnet was converted to heat. But you could also say that the energy of the field was converted to heat in a relatively direct manner.

Yes but the question was what carries the energy in current. The part lost to resistance is no longer part of the current.
 
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  • #52
I guess that means the part lost in the device you are running is also no longer part of the current?
You don't lose current in a resistor. The current stays the same, what you loose is potential.
 
  • #53
scoobmx said:
The electric and magnetic fields carry the energy, but the movement of electrons is influenced by these fields. I have always thought of the kinetic energy of the electrons as mechanical energy, that become heat when they scatter on impurities (the phenomenon of resistance).
Have you not read all the preceding posts that tell you the amount of KE carried by electrons is as near zero as makes no difference? Resistive wire can get pretty hot. Where would the energy come from if it relied on electron KE?

You could prove this for yourself if you work out the actual mass of all the conduction electrons in a wire and then multiply it by v2/2 , with mean v = 1mm/s.
 
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  • #54
sophiecentaur said:
Have you not read all the preceding posts that tell you the amount of KE carried by electrons is as near zero as makes no difference? Resistive wire can get pretty hot. Where would the energy come from if it relied on electron KE?

You could prove this for yourself if you work out the actual mass of all the conduction electrons in a wire and then multiply it by v2/2 , with mean v = 1mm/s.

That 1 mm / s is the drift velocity, not the actual velocity. Even at 0 drift velocity electrons have kinetic energy that approximately follows the equipartition theorem (hence 'electron gas').

If truly electrons carried the energy in the circuit then when you flip a light switch you would have to wait for the 1 mm / s electrons to crawl to the light bulb. But we all know it's nearly instantaneous. It's the electromagnetic field that conveys the energy.
 
  • #55
scoobmx said:
That 1 mm / s is the drift velocity, not the actual velocity. Even at 0 drift velocity electrons have kinetic energy that approximately follows the equipartition theorem (hence 'electron gas').

If truly electrons carried the energy in the circuit then when you flip a light switch you would have to wait for the 1 mm / s electrons to crawl to the light bulb. But we all know it's nearly instantaneous. It's the electromagnetic field that conveys the energy.

I thought we'd been there before / knew that. That post of mine that you are quoting is a (several times) repeated reply which tried to knock the electron KE idea on the head. It was just a suggestion to try it out for himself.
 
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