Kinetic Energy of 10kg Object Dropped from 100m

AI Thread Summary
To calculate the kinetic energy of a 10 kg object dropped from a height of 100 m, the relevant formula is KE = 0.5 * m * v^2, where m is mass and v is velocity. The velocity just before impact can be determined using the equation v = g * t, with g set at 10 m/s². After falling for a duration calculated from the height, the velocity is found to be 40 m/s. Substituting this value into the kinetic energy formula yields a kinetic energy of 8000 joules right before impact. The discussion emphasizes the importance of understanding the relationship between potential and kinetic energy in free-fall scenarios.
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Homework Statement

A 10 kg object is dropped from 100m above. What is the kinetic energy of the object right before it hits the ground?

(Assume: g= 10 m/s^2)

Homework Equations



(Assume: g= 10 m/s^2)

The Attempt at a Solution



I got 100 right before it hits the ground..
 
Last edited:
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What is your attempt at the solution?
 


sernewto said:

Homework Equations



(Assume: g= 10 m/s^2)

What theory/formula do you think you need to use for this problem?
 

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