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Kinetic Energy of a Charge

  1. Feb 11, 2008 #1
    [SOLVED] Kinetic Energy of a Charge

    1. The problem statement, all variables and given/known data
    A charged particle q, which is fixed in position, produces an electric potential of 3.10E2 V at a distance of 1 m away (the potential from q vanishes at infinity). If a particle of charge Q=.00500 C is released from rest at a distance of 7.00 m from q, what will be its kinetic energy after moving very far from q?


    2. Relevant equations
    V = Ed
    E = Fq
    KE = q(V_initial-V_final)

    3. The attempt at a solution
    Since V_initial is given at 310 V, I need to solve for V_final.

    Since V = Ed, I solved for the electric field of Q:

    E=kq/d^2

    E=(9x10^9)(.005)/7^2
    E=10285714.29

    Then, since V=Ed
    V = 10285714.29.

    This is where I get confused because I don't think this is a realistic number since V initial was 3.10E2. Please help. I think all I need to do is find V_final to solve the problem, but I am not doing it right. Am I going about this the correct way?

    SOLVED: Nevermind, figured it out.
     
    Last edited: Feb 11, 2008
  2. jcsd
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