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ttiger2k7
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[SOLVED] Kinetic Energy of a Charge
A charged particle q, which is fixed in position, produces an electric potential of 3.10E2 V at a distance of 1 m away (the potential from q vanishes at infinity). If a particle of charge Q=.00500 C is released from rest at a distance of 7.00 m from q, what will be its kinetic energy after moving very far from q?
V = Ed
E = Fq
KE = q(V_initial-V_final)
Since V_initial is given at 310 V, I need to solve for V_final.
Since V = Ed, I solved for the electric field of Q:
E=kq/d^2
E=(9x10^9)(.005)/7^2
E=10285714.29
Then, since V=Ed
V = 10285714.29.
This is where I get confused because I don't think this is a realistic number since V initial was 3.10E2. Please help. I think all I need to do is find V_final to solve the problem, but I am not doing it right. Am I going about this the correct way?
SOLVED: Nevermind, figured it out.
Homework Statement
A charged particle q, which is fixed in position, produces an electric potential of 3.10E2 V at a distance of 1 m away (the potential from q vanishes at infinity). If a particle of charge Q=.00500 C is released from rest at a distance of 7.00 m from q, what will be its kinetic energy after moving very far from q?
Homework Equations
V = Ed
E = Fq
KE = q(V_initial-V_final)
The Attempt at a Solution
Since V_initial is given at 310 V, I need to solve for V_final.
Since V = Ed, I solved for the electric field of Q:
E=kq/d^2
E=(9x10^9)(.005)/7^2
E=10285714.29
Then, since V=Ed
V = 10285714.29.
This is where I get confused because I don't think this is a realistic number since V initial was 3.10E2. Please help. I think all I need to do is find V_final to solve the problem, but I am not doing it right. Am I going about this the correct way?
SOLVED: Nevermind, figured it out.
Last edited: