[SOLVED] Kinetic Energy of a Charge 1. The problem statement, all variables and given/known data A charged particle q, which is fixed in position, produces an electric potential of 3.10E2 V at a distance of 1 m away (the potential from q vanishes at infinity). If a particle of charge Q=.00500 C is released from rest at a distance of 7.00 m from q, what will be its kinetic energy after moving very far from q? 2. Relevant equations V = Ed E = Fq KE = q(V_initial-V_final) 3. The attempt at a solution Since V_initial is given at 310 V, I need to solve for V_final. Since V = Ed, I solved for the electric field of Q: E=kq/d^2 E=(9x10^9)(.005)/7^2 E=10285714.29 Then, since V=Ed V = 10285714.29. This is where I get confused because I don't think this is a realistic number since V initial was 3.10E2. Please help. I think all I need to do is find V_final to solve the problem, but I am not doing it right. Am I going about this the correct way? SOLVED: Nevermind, figured it out.