Kinetic Energy of a Particle in a semi-spherical bowl

AI Thread Summary
The problem involves calculating the kinetic energy of a 410 g particle in a semi-spherical bowl after being released from rest. The particle's speed at point B is given as 2.6 m/s, and the relevant equation for kinetic energy is KE = (1/2)mv^2. The initial calculation of kinetic energy resulted in 1385.8, but there was a reminder to work with units to avoid mistakes, as joules are defined as N⋅m. Correct unit handling is crucial for accurate results in physics problems.
Joshua Lee
Messages
10
Reaction score
0

Homework Statement


A 410 g particle in a semi-spherical bowl of radius 0.9 m is released from rest at point A at the level of the center of the bowl, and the surface of the bowl is rough. The speed of the particle at B is 2.6 m/s. The acceleration of gravity is 9.8 m/s 2 . What is its kinetic energy at B? Answer in units of J.

Homework Equations


KE= (1/2)mv^2

The Attempt at a Solution


KE= (1/2)(410)(2.6)^2= 1385.8
 
Physics news on Phys.org
You should work with units, that would have helped you to spot your mistake here.
 
Remember that a joule is equal to 1 N⋅m
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Kinetic Energy of a Cylinder Rolling Without Slipping
Replies
21
Views
4K
Using energy considerations to analyse particle motion
Replies
3
Views
827
Potential and Kinetic energy equations including drag coefficient
Replies
1
Views
1K
How Is Potential Energy Converted to Kinetic Energy in Physical Systems?
Replies
6
Views
1K
Confused about a conservation of energy problem
Replies
4
Views
2K
Kinetic Energy of a Charged Particle near a Charged Ring
Replies
2
Views
1K
Analysis of collisions from data
Replies
2
Views
1K
Calculating Kinetic & Potential Energy: Is it Correct?
Replies
12
Views
1K
Kinetic energy in center of mass reference frame
Replies
3
Views
1K
Work done during a collision -- Change in Kinetic Energy & change in Momentum
Replies
1
Views
2K

Hot Threads

Recent Insights

Back
Top