Kinetic energy of alpha particle during decay

AI Thread Summary
The discussion focuses on calculating the kinetic energy acquired by an alpha particle during alpha decay, represented by the formula Talpha=Q/[1+[maplha/mD]. The energy release, Q, is defined as the difference in mass-energy between the parent nucleus and the daughter nucleus plus the alpha particle, given by Q=[mP-mD-malpha]c^2. Participants emphasize the importance of applying conservation of energy and momentum to determine how kinetic energy is distributed between the alpha particle and the daughter nucleus. This approach leads to a unique solution for the kinetic energy of each particle involved in the decay process. Understanding these principles is crucial for accurately analyzing alpha decay dynamics.
senan
Messages
17
Reaction score
0

Homework Statement



Show that kinetic energy acquired by an alpha particle during an alpha decay is

Talpha=Q/[1+[maplha/mD]


Homework Equations



Q=[mP-mD-malpha]c^2


The Attempt at a Solution



Q is the release of energy which is acquired by the daughter nucleus and the alpha particle in the form of KE. I'm just not sure how to determine the KE will be split between the two
 
Physics news on Phys.org
Apply conservation of energy in conjunction with conservation of momentum. This will lead to a unique solution for the kinetic energy possessed by each particle.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top