Kinetic Energy & Work Question? (Halliday, Resnick, Walker, 7e, Ch. 7 #39)

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SUMMARY

The discussion centers on a physics problem from Halliday, Resnick, and Walker's "Fundamentals of Physics" (7th Edition, Chapter 7, Problem 39) involving kinetic energy and work. The scenario describes a cart sliding along a frictionless rail while a cord with a constant tension of 25.0 N is pulled over a pulley. The user initially calculated the work done as 42.9 J, but the correct answer is 41.7 J, which requires considering the changing angle of the cord during the cart's movement. The solution involves integrating or applying conservation principles to account for the variable angle.

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Homework Statement


A cord is attached to a cart that can slide along a frictionless horizontal rail aligned along an x axis. The left end of the cord is pulled over a pulley, or negligible mass and friction and at cord height h = 1.20m, so the cart slides from x1 = 3.00m to x2 = 1.00m. During the move, the tension in the cord is a constant 25.0N. what is the change in the kinetic energy of the cart during the move?


Homework Equations



W=Fxcos[tex]\Theta[/tex]d ?
[tex]\Delta[/tex]K= 1/2mv22F - 1/2mv2I ?

The Attempt at a Solution



I attempted to find theta by doing tan-1(1.2/2) getting angle 31.96 degrees. I then plugged that into Fxcos(31.96)d = 25Ncos(31.96)2.00m = 42.9J which was my answer. But the book says it's 41.7J. I just can't figure it out...
 
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welcome to pf!

hi math_head7! welcome to pf! :smile:

(have a theta: θ and a delta: ∆ and a degree: ° :wink:)

i assume the lower end of the string stays 1.2 m below the pulley, so that the angle changes?

you've calculated it as if the angle stays the same :redface:

you'll need to integrate (alternatively, there is a trick using conservation) :wink:

try again! :smile:
 
Thanks tiny-tim.

I didn't consider at all that θ was changing. Thanks to that advice I was able to figure it out.
 

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