Know Eigenvalue and Eigenvector, How Do I Figure Out a Possible Original Matrix?

MikeDietrich
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Homework Statement


This is a general question... I can easily go from a matrix A to its eigenvalues and then eigenvectors but how would I go from the eigenvalues and eigenvectors to a feasible original matrix?

Any thoughts appreciated!
 
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Start with how are the original matrix A and the diagonal matrix D related and then solve for A.
 
To expand on vela's response- presumably you know that if A has n independent eigenvectors (where A is an n by n matrix) then, with P the matrix having those eigenvectors as columns, PAP^{-1}= D where D is the diagonal matrix with the eigenvalues of A on the diagonal. From that, A= P^{-1}DP. If you are given the eigenvalues and eigenvectors of A, you can form both P and D from that information and so find A.

If A is not diagonalizable (does not have n independent eigenvectors), then it is a little harder but the same idea- D will be the Jordan Normal Form matrix with eigenvalues along the diagonal and possibly "1"s above the diagonal. There will be fewer than n eigenvectors so you will have to supplement them with "generalized eigenvectors" to form the matrix P. Fortunately, the generalized eigenvectors of A are the same as those of D so that can be done.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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