L^p spaces are not equivalent for infinite measure sets

JasonJo
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Find a function f such that f is in L^P(R) but not in L^Q(R) for p not equal to q, where R is the set of real numers.

I'm guessing I need to find a function that only blows up when it is raised to the qth power, but I am having some difficulty proving this.
 
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Try finding some function f that's in L^1 but not in L^2. To make things easier, you can choose a compactly-supported f.
 
I suppose just f = sin would do!
 
It wouldn't, because sin isn't in any L^p(R) space. :-p
 
Oh, right!:blushing:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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