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I Lagrangian density meson

  1. Mar 11, 2016 #1
    upload_2016-3-12_12-21-2.png

    My question is why there is -1/2 for ω meson?
     
  2. jcsd
  3. Mar 12, 2016 #2
    Where did you find these lagrangians?
    I would remove the (-)1/2( ...) bit.
    Then it can be correct if σ is complex and ω is real valued.
     
  4. Mar 12, 2016 #3

    vanhees71

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    No, you shouldn't remove the ##-1/2## ;-), because it's correct. You obviously work in the east-coast metric, where ##(\eta_{\mu \nu})=\mathrm{diag}(1,-1,-1,-1)##. The physical degrees of freedom of ##\omega^{\mu}## are three space like vectors, and thus to get the right sign for the kinetic and the mass term there must be that additional - sign.
     
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