Laminar flow exits an inclined tube

AI Thread Summary
The discussion centers on modeling the behavior of viscous Newtonian fluid exiting an inclined tube, forming a fountain-like flow. Key considerations include the relationship between the fountain's height and the pipe diameter, as well as the impact of nearby surfaces on fluid dynamics. Participants explore the possibility of deriving asymptotic relations for the depth-averaged radial exit velocity distribution, particularly when the surface is inclined. The conversation highlights that while the flow inside the tube follows a parabolic profile, the dynamics change significantly near the exit, suggesting that numerical simulations may be necessary for accurate modeling. Overall, the complexity of fluid behavior in this scenario is acknowledged, emphasizing the need for further research and computational approaches.
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I am working on a problem in which viscous flow comes out from an inclined tube, forming some kind of a fountain. In the tube the fluid is Newtonian and the flow can be treated as Poiseuille flow. I want to study the movement of the fluid after it leaves the tube. Can someone point me about the existing study and research on this? Thanks.
 
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It comes out from the top end of the inclined tube?
 
siddharth23 said:
It comes out from the top end of the inclined tube?
Yes
 
Is the fountain very high/large compared to the diameter of the pipe? Is there a good reason to expect a large deviation from a ballistic trajectory?
 
mfb said:
Is the fountain very high/large compared to the diameter of the pipe? Is there a good reason to expect a large deviation from a ballistic trajectory?
I attached a photo of the experiment I am trying to model. The fluid has significant deformation.
 

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Oh, and with a surface nearby, then things get complicated.
 
mfb said:
Oh, and with a surface nearby, then things get complicated.
Yes. Is it possible to get some asymptotic relation of the depth averaged radial exit velocity (parallel to the surface) distribution? I mean, if the surface is horizontal, surely the exit velocity is a constant and depth are the same. When the surface has an inclination \alpha, my guess is that the flux per length behaves like
Q=\oint\boldsymbol{n}\cdot\boldsymbol{u}h dl\sim\int_{-\pi}^{\pi}\Gamma(\alpha,\theta)rd\theta,
where r is the radius of the tube, and the flux \Gamma satisfies
\Gamma(\alpha,-\pi)=\Gamma(\alpha,\pi)=0,\,\Gamma(\alpha,-\theta)=\Gamma(\alpha,\theta),\,\Gamma(0,\theta)=\text{constant}.

I do not need to solve the exact trajectory of the fluid, an approximated distribution of \Gamma is enough.
 
Inside the tube and far away from the exit, flux should still follow a parabolic profile. Close to the exit, things get different. For a horizontal surface, the exiting water will fall back on the stream, and then I don't see how you could avoid numerical simulations. Those are a good idea for inclined planes as well, I think.
 
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