Laplace equation in spherical coordinates

AI Thread Summary
The discussion revolves around solving the Laplace equation inside a sphere with a specific boundary condition. The user successfully derived the general solution but struggled to match it with the boundary condition, leading to the conclusion that certain coefficients must be zero. They identified that only the solution for l=1 is relevant, but the Legendre polynomials do not match the boundary conditions. Guidance was provided to focus on finding the values of the coefficients by comparing the boundary condition at r=3 with associated Legendre polynomials. Ultimately, the user expressed gratitude for the assistance and indicated they may have resolved the issue.
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Homework Statement



Solve the Laplace equation inside a sphere, with the boundary condition:

\begin{equation}
u(3,\theta,\phi) = \sin(\theta) \cos(\theta)^2 \sin(\phi)
\end{equation}

Homework Equations


\begin{equation}
\sum^{\infty}_{l=0} \sum^{m}_{m=0} (A_lr^l + B_lr^{-l -1})P_l^m(\cos \theta) [S_m\sin(m\phi) + C_m\cos(m\phi)]
\end{equation}

The Attempt at a Solution


I have derived the general solution for the Laplace equation in spherical problems and that went okej. The problem is when I try to match it with the boundary conditions. If I use the method of identification it is imminently obvious that:
\begin{equation}
C_m=0, m=1 \text{ and that for} \quad l\neq1 \rightarrow A=0
\end{equation}
, m has to equal one so the arguments of sin is correct and A=0 so the solution does not blow up, when r approaches 0. Which means I have two different solutions: one where l=1 and another solution for all the rest of l´s. When l equals one the Legendre polynomials dose not match the boundary conditions so that solution can be discarded.

Which means that I have an equation that looks like:

\begin{equation}
\sum^{\infty}_{l=0} ( B_l3^{-l -1})P_l^1(\cos \theta) S_1\sin(\phi) = \sin(\theta) \cos(\theta)^2 \sin(\phi)
\end{equation}

When I look at table's for Legendre polynomials I do not find any that looks like it can solve my equation. I would really appreciate some guidance in the right direction.
 
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\begin{equation}
\sum^{\infty}_{l=0} \sum^{m}_{m=0} (A_lr^l + B_lr^{-l -1})P_l^m(\cos \theta) [S_m\sin(m\phi) + C_m\cos(m\phi)]
\end{equation}
Typo: what is the upper limit of the summation over ##m##?

You are dealing with the interior of a sphere. So, you don't need to worry about ##r## going to infinity. However, what happens to ##r^{-l-1}## at the center of the sphere?
 
The upper limit of the summation is suppose to be l.

I have singularity there, so the constant B has to be zero. Thanks.
 
No one that can help me?
 
Looks like now you just need to find the values of the ##A_l## coefficients by considering the boundary condition at r = 3. Look at a table of ##P_l^1(\cos \theta)## to see which ones can be used to obtain ##\sin \theta \cos^2 \theta##.
 
That is what I have trying to do, quite unsuccessfully so far. But I know now at least that this is the way to do it, so thank you.
 
Hint: Look at your boundary condition at r = 3 and compare to a table of associated Legendre polynomials.
 

Attachments

  • Assoc Legendre Polynomials.png
    Assoc Legendre Polynomials.png
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Last edited:
I think I solved it. Thanks for all the help!
 
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