- #1

- 360

- 0

i know that

L{f(t)} = [tex]\int[/tex]e

^{-st}f(t) dt = F(s)

so

L{f(t/b)} = [tex]\int[/tex]e

^{-st}f(t/b) dt

any tips on how to start? thx

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter magnifik
- Start date

- #1

- 360

- 0

i know that

L{f(t)} = [tex]\int[/tex]e

so

L{f(t/b)} = [tex]\int[/tex]e

any tips on how to start? thx

- #2

Dick

Science Advisor

Homework Helper

- 26,260

- 619

Do a u substitution to change the integration variable. Substitute u=t/b.

- #3

- 360

- 0

do i also have to plug in (t/b) into e^{-st} so that it becomes e^{-s(t/b)} ?

- #4

Dick

Science Advisor

Homework Helper

- 26,260

- 619

do i also have to plug in (t/b) into e^{-st}so that it becomes e^{-s(t/b)}?

You need to write e^(-st) in terms of u.

- #5

- 360

- 0

so..

u = t/b

t = bu

e^(-st)

e^(-sbu)

u = t/b

t = bu

e^(-st)

e^(-sbu)

- #6

Dick

Science Advisor

Homework Helper

- 26,260

- 619

so..

u = t/b

t = bu

e^(-st)

e^(-sbu)

Sure. Now don't forget to add a factor to change the dt to a du.

Share:

- Replies
- 0

- Views
- 3K