Laplace Transformation: Transforming F(s) = 1/(s-2)^2

[leopard]

How can I transform

F(s) = \frac{1}{(s-2)^2}

?

I cannot see that any of the functions in my table is useful...

 

[gabbagabbahey]

Use the third one in the list along with the "frequency shifting rule": \mathcal{L}^{-1}[F(s-\alpha)]=e^{\alpha t}\mathcal{L}^{-1}[F(s)]

 

[HallsofIvy]

Actually, it's the second one in the list: the Laplace transform of 1/t is 1/s². I think gabbagabbahey was counting the heading. Also note that gabbagabbahey's "frequency shifting rule" is implied in the third, the Laplace transform of e^at is 1/(s-a) which is just the laplace transform of 1/t "shifted" by a.

 

[gabbagabbahey]

... I think gabbagabbahey was counting the heading...

Actually I meant the third (with n=1 of course)---but certainly the second is a little more straightforward!