Largest possible radius homework problem

AI Thread Summary
The problem involves finding the largest radius of a sphere that can fit inside a 100 mm cube while touching a wire inserted 20 mm from two adjacent edges. Using the Pythagorean theorem, the calculated radius is 47 mm. The geometry of the cube and the positioning of the wire are crucial for determining the sphere's size. The solution emphasizes visualizing the problem with a top view for better understanding. The final answer, rounded to the nearest mm, is 47 mm.
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Homework Statement



A 100 mm cube has a thin and rigid wire inserted 20 mm from each of two adjacent edges ,as shown.The cube contains a sphere that is not cut by the wire .What is the largest possible radius ,to the nearest mm, of the sphere that just touches the wire?

Homework Equations





The Attempt at a Solution



Some hints ?
 

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thereddevils said:

Homework Statement



A 100 mm cube has a thin and rigid wire inserted 20 mm from each of two adjacent edges ,as shown.The cube contains a sphere that is not cut by the wire .What is the largest possible radius ,to the nearest mm, of the sphere that just touches the wire?

Homework Equations





The Attempt at a Solution



Some hints ?

Here's a top view, drawn to scale. That's my hint:

forumsphereincube.jpg
 


LCKurtz said:
Here's a top view, drawn to scale. That's my hint:

forumsphereincube.jpg

that's a great hint, thanks! I got r=47mm by phythagoras.
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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