How Does Beam Size Change with Increased Span in Building Construction?

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In building construction, increasing the beam span from 6 to 12 meters does not result in a simple doubling of beam and column sizes; rather, the relationship is more complex due to the physics involved. The moment calculations for point and uniform loads indicate that the span length significantly influences the required beam depth, as the moment from uniform loads is proportional to the square of the span. The moment of inertia, which is crucial for beam strength and stiffness, is affected by the beam's height cubed, making height increases more impactful than width. Additionally, the choice of beam shape, such as I-beams for steel construction, optimizes the distribution of material for strength. Overall, the design must consider various load types and the self-weight of the beam alongside other loads.
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Supposed in builiding contruction, the beam span is 12 meters compared to 6 meters. Would it make the beam size (and column size) twice in the longer 12 meters span given the same loading? Is there a law of physics that says the sizes are proportional to the span? Or is it algorithmic or nonlinear?

Don't worry. I'm not going to construct the builiding myself, of course. Just wondering how the beam depth would increase if the span requirement is greater. If you have any formula to give an idea what is the relationship, do let me know.. thanks a lot.
 
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The load type will make a difference, point load vs uniform loads. The beam depth but more specificly the section modulus and moments of inertia determine the strength and stiffness of the beam, and of course the material strength.

P = point load
L = Span Length
W = uniform load (kip/ft or kN/m)

Moment from point load = P*L / 4 assuming (simple supports)
Moment from uniform load = W L2 / 8 assuming (simple supports)

As you can see for uniform loads (most typical) the length term is squared.

b = beam width
h = beam height
I = moment of inertia (rectangluar beam = b*h3 / 12)
For simplicty (and normally only in simple timber construction we assumed a rectangular shape) you see the height of the beam is a cubed term hence it is very significant.
We would in steel normally use a roughly "I" shaped beam because it efficently provides big moments of inertia by concentraiting the larger areas at the higher stressed locations. The web is then assumed to only carry shears.

y = half of beam height for this case.
σ(stress) = M *y / I = M/S

It is always necessary to account for the selfweight of the beam and other supporting elements in addition to any supported live, dead or environmental loads.
 
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