Effect of Adding NaOH to a Solution of K2CrO4 at Equilibrium

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Adding NaOH to a solution of K2CrO4 affects the equilibrium by neutralizing the H+ ions present in the solution. According to Le Chatelier's principle, this removal of acid will shift the equilibrium to the left to replace the lost H+ ions. The reaction involved is 2CrO4 (aq) + 2H+(aq) ⇌ Cr2O7(aq) + H2O. Therefore, the addition of NaOH, a base, results in a shift towards the reactants. This demonstrates the dynamic nature of chemical equilibria and the impact of concentration changes on reaction direction.
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Le chatelier's principle..HELP!

1. for the given reaction at equilibrium predict what would happen if NaOH were added to a solution of K2CrO4



2. 2CrO4 (aq) + 2H+(aq) --> Cr2O7(aq) + H2O



3. my answer was that it would not affect the equilibrium since NaOH is a liquid :confused: but I am nott suure :frown:

all help will be greatly appreciatedd :blushing:
 
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What happens when sodium hydroxide is added to an acidic solution?
 
neutralization reaction?..so that means the reaction will proceed in the forward direction?
 
In your equation, where is the acid? If you neutralize it, what direction will the reaction proceed to reestablish equilibrium.

PS. Your arrow needs to be a double-headed arrow to indicate an equilibrium condition (an absolute requirement for any application of Le Chatelier's principle).
 
so basically da H+ is the acid..cuz acids donate a proton..so therefore the reactino will proceed in the forward direction to reduce the stress of NaOH...? need to know if I am right =)
 
btw ye i know it needs to be a double arrow, i just didnt know how to put it
 
Shift comma, hyphen, hyphen, hyphen, hyphen, shift period.

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You don't have it yet... Think about removing some of the acid. What direction will the reaction proceed to replace it?
 
ohhh..k..so wen NaOH is added it takes up the proton since its a base..so therefore the reaction will proceed to the left =)
 
Final answer?
 
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um..yeaaa..:|
 
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