Learning physics on my own need a little help

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To determine the direction of a person walking 3.0 km North and 4.0 km East, trigonometry is used, specifically the tangent function. The angle θ can be calculated using the formula Tanθ = opposite/adjacent, which in this case is 4 km (East) over 3 km (North). This results in θ = tan-1(4/3), yielding an angle of approximately 36.9 degrees. The final direction is expressed as [N 36.9° E]. This method effectively combines basic trigonometric principles with directional analysis.
oG riT
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what is the direction of a person that walks 3.0-km North and 4.0-km East?
and can you tell me how you got the answer please
 
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oG riT said:
what is the direction of a person that walks 3.0-km North and 4.0-km East?
and can you tell me how you got the answer please
Hello oG riT. Welcome to PF !

To answer your question, you need to use trigonometry.

Is that question worded exactly as it was given to you in the textbook?
 
Use Tan function to find the angle. (θ represents an angle)
Tanθ = opp/adj
= 4km / 3km
θ = tan-1(4km/3km)

So the direction would be [N θ E]
 
yes that's how it was worded
 
Ace. said:
Use Tan function to find the angle.


(θ represents an angle)
Tanθ = opp/adj
= 4km / 3km
θ = tan-1(4km/3km)

So the direction would be [N θ E]

i got 36.9 is that right?
 

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