LED 'ON' light across power switch

AI Thread Summary
To install an LED indicator light across the main power switch for a 12V boat battery, it is essential to wire the LED in parallel with the hot side of the battery wire, using a current-limiting resistor in series. A typical setup involves using an 800-ohm resistor for a standard LED, ensuring it operates safely without shorting the circuit if it fails. It's crucial to connect the LED correctly, noting that the longer lead is the positive one. Alternatively, a pre-assembled LED with a built-in resistor can be purchased for convenience. Proper wiring will allow the LED to illuminate only when the power switch is on, providing a clear indication of the power status.
DaveC426913
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I wish to attach an LED indicator light across the main power to the 12V battery on my boat. This light will let me know from a convenient location whether I've remembered to switch off the main power.

How do I wire it up?

The LED is obviously 3V.
The light would only be ON if the power switch is on.
If the LED fails, I don't want it to kill the power.
Do I simply splice it in parallel with the hot side of the battery wire?
 
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The LED is not "obviously" 3V at all! And this is not how you calculate LED circuits. If it's a vanilla LED without internal resistor, then it has a voltage drop of 1.7 V and the remaining Voltage over the pre-resistor will be used to adjust the current.
I would try a 800Ohms resistor in series with the diode which would give around 15mA with 12 V or a 700Ohms one if it is indeed specified to run directly on 3V. But you would do best to check the specs of the diode to see what currents you can use. If your diode burns then it shouldn't shortcut, but even if it did it will not be a problem.

http://www.theledlight.com/LED101.html
 
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You could also (as I would) just use a small 12V incandescent bulb such as from a car dashboard wired in parallel.
 
0xdeadbeef said:
i would try a 800ohms resistor in series with the diode which would give around 15ma with 12 v

(12 - 1.7) / .015 = 686.7 Ohms.

A more conservative drive level for typical GaAs LEDs (which normally have a 20 mA max forward current) is 10 mA, so use a ~1k resistor.
 
DaveC426913 said:
I wish to attach an LED indicator light across the main power to the 12V battery on my boat. This light will let me know from a convenient location whether I've remembered to switch off the main power.

How do I wire it up?

The LED is obviously 3V.
The light would only be ON if the power switch is on.
If the LED fails, I don't want it to kill the power.
Do I simply splice it in parallel with the hot side of the battery wire?
You could just go to Radio Shack and purchase a http://www.radioshack.com/family/index.jsp?categoryId=2032293" which has a current limiting resistor built in.
 
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How do I wire it up?


You would wire the resistor in series with the LED (as above) between the cold side of the switch and ground.
When you apply power to the load, you would also apply power to the LED / resistor combination.

LEDs have to be the right way around and usually have one lead longer than the other and this is the positive lead.
 
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vk6kro said:
How do I wire it up?


You would wire the resistor in series with the LED (as above) between the cold side of the switch and ground.
When you apply power to the load, you would also apply power to the LED / resistor combination.
Got it.

I feel embarrassed, having taken basic electronics in night school. Seem to have forgotten much of it.

vk6kro said:
LEDs have to be the right way around and ususally have one lead longer than the other and this is the positive lead.
Yes. This much I knew.


Thank y'all.
 
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