Legendre Expansion solution to sphere of potential V with charge q outside

AI Thread Summary
The discussion focuses on solving the potential V of a sphere with a charge q located outside at a distance d, specifically using Legendre polynomials. The original poster acknowledges the general solution to the Laplace equation in spherical coordinates but seeks guidance on incorporating an image charge into this framework. They mention that an image charge can be placed inside the sphere, but they are unsure how to integrate this with Legendre polynomials. Responses clarify that while the image charge method is valid, the poster is specifically looking for a solution that utilizes Legendre polynomials for this scenario. The conversation emphasizes the need for examples or a detailed approach to apply Legendre expansions in this particular case.
phys_student1
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Hi,

It seems that there is no much examples of this particular case.

OK, we all know how to write the general solution to Laplace equation in spherical coordinates in terms of Legendre polynomials (when there is azimuthal symmetry).

There are a lot of cases here but I would like to know how to attack the problem of a sphere held at potential V with a charge 1 outside a distance d.

I know you will have an image charge inside the sphere a distance d*a^2 from sphere's center.

But how to account for this system of image charge and original charge? Can we simply add a term (outside the sum of Legendre Polynomial) ?

Thanks in advance
 
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You can put an image charge, q"=V/a+qa/d, at the center of the sphere of radius a.
You don't need Legendre polynomials for this.
The original image charge should be at d'=a^2/d.
 
Meir Achuz said:
You can put an image charge, q"=V/a+qa/d, at the center of the sphere of radius a.
You don't need Legendre polynomials for this.
The original image charge should be at d'=a^2/d.

I understand the image charge method.

What I seek is the solution utilizing Legendre Polynomials.

Again, I understand Legendre Polynomial solution as applied to different cases, but not this one.
 
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