LeGrange multiplier with inequality

[memish]

Homework Statement

Find the dimensions of the box with the largest volume, given the constraint that the perimeter of the cross sector perpendicular to length is at msot 108

Homework Equations

So I have f(x,y,z)=xyz
and the constraint is 2x+2z<108

The Attempt at a Solution

I set up the legrange multipler <yz, xz, xy>=(multiplier)<2, 0, 2>
So then you have
yz=2(multiplier)
yx=2(multiplier)
xz=0(multiplier)
and then 2x+2z<108
But since xz=0(m), I can't figure out how to solve the 4 equations to get the possible points. If I have xz=0, then either x or z is 0, right? but then there would be no volume..any ideas? Thanks!

 

[LCKurtz]

You probably have the problem stated incorrectly. As stated, the volume has no max because you could take y as large as you want no matter what x and z are.

Re-read the problem. My guess is that it will say something like "the length of the box plus the perimeter" is bounded.