Length contraction equation. what am i doing wrong?

AI Thread Summary
The discussion revolves around the length contraction equation and the user's struggle to correctly calculate the velocity (v) without exceeding the speed of light (c). The user initially misapplies the equation, leading to incorrect results. A key correction is provided, indicating that the user made a sign error when simplifying their equations. After correcting this mistake, the user finds that the velocity is approximately 0.661c, which is within the acceptable range. The conversation emphasizes the importance of careful algebraic manipulation in physics calculations.
Sneil
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Length contraction equation determining v. what am i doing wrong?

OK,

L=L*(1-v2/c2)1/2 (to the power of 1/2)

L=.75m L*=1.0m

now i need to find v and for the life of me i always end up with a value greater then c which is obviously impossible.

ill simplify to v=

L/L*=(1-v2/c2)1/2
(L/L*)squared = 1-v2/c2
1+(L/L*)squared = v2/c2
(1+(L/L*)squared )to the 1/2=v/c
c((1+(L/L*)squared )to the 1/2)=v

and thus i break the barrier of the speed of light and go back in time i guess...

any help?? asap please :redface:
 
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Sneil said:
OK,

L=L*(1-v2/c2)1/2 (to the power of 1/2)

L=.75m L*=1.0m

now i need to find v and for the life of me i always end up with a value greater then c which is obviously impossible.

ill simplify to v=

L/L*=(1-v2/c2)1/2
(L/L*)squared = 1-v2/c2
1+(L/L*)squared = v2/c2
(1+(L/L*)squared )to the 1/2=v/c
c((1+(L/L*)squared )to the 1/2)=v

and thus i break the barrier of the speed of light and go back in time i guess...

any help?? asap please :redface:
Your mistake is on line 3. It should go:
(\frac{L}{L*})^2=1-\frac{v^2}{c^2}
(\frac{L}{L*})^2-1=-\frac{v^2}{c^2}
\frac{v^2}{c^2}=1-(\frac{L}{L*})^2
 
Sneil said:
OK,

L=L*(1-v2/c2)1/2 (to the power of 1/2)

L=.75m L*=1.0m

now i need to find v and for the life of me i always end up with a value greater then c which is obviously impossible.

ill simplify to v=

L/L*=(1-v2/c2)1/2
(L/L*)squared = 1-v2/c2
1+(L/L*)squared = v2/c2
(1+(L/L*)squared )to the 1/2=v/c
c((1+(L/L*)squared )to the 1/2)=v

and thus i break the barrier of the speed of light and go back in time i guess...

any help?? asap please :redface:

Let's see. L/L* is .75

(1 - v^2/c^2)^1/2 -.75
1 - v^2/c^2 = .5625
-v^2/c^2 = .5625 -1 = -.4375
v^2/c^2 = .4375
v/c = sqrt(.4375) = .661437828

So v is about 661/7 % of c.

Your error was in going from your second equation to your third. You got the signs wrong in simplifying. Check it out.
 
ah, great. bad mistake on my part. Thank you very much for the quick replies! :smile: :smile:
 
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