Length contraction of two spaceships

AI Thread Summary
Two spaceships, each 100 meters long at rest, are traveling toward each other at 0.85c relative to Earth. The initial attempt to calculate their relative velocity using Newtonian mechanics yields an impossible result of 1.5c. To correctly determine the relative velocity, the appropriate equation from Einstein's theory must be applied. The formula for relative velocity between two objects moving at relativistic speeds is v_BA = (v_B - v_A) / (1 - (v_A * v_B / c^2)). Understanding and applying this equation is crucial for solving the problem accurately.
Saxby
Messages
45
Reaction score
0

Homework Statement


Two space ships, each a hundred metres long when measured at rest, travel toward each other with a speed of 0.85c relative to the Earth.


Homework Equations


λ = 1 / √1 - (v2/c2)
x' = λ(x - vt)
L' = L / λ

The Attempt at a Solution


Well to be honest i may be missing an equation or something but that's what i was given.

I find that the relative velocity of one spaceship to another (according to Newton) would be 1.5c. This doesn't work using the equations above. I know i have to find the relative velocity according to Einstein's theory but i don't know how.
 
Physics news on Phys.org
Saxby said:

Homework Statement


Two space ships, each a hundred metres long when measured at rest, travel toward each other with a speed of 0.85c relative to the Earth.


Homework Equations


λ = 1 / √1 - (v2/c2)
x' = λ(x - vt)
L' = L / λ

The Attempt at a Solution


Well to be honest i may be missing an equation or something but that's what i was given.

I find that the relative velocity of one spaceship to another (according to Newton) would be 1.5c. This doesn't work using the equations above. I know i have to find the relative velocity according to Einstein's theory but i don't know how.
So, you are trying to find the relative velocity of one to the other?

Let the first spaceship be spaceship A and the second be spaceship B.

Consider ##v_{BA}=\frac{v_B-v_A}{1-\frac{v_Av_B}{c^2}}##.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
36
Views
3K
Replies
3
Views
2K
Replies
2
Views
2K
Replies
5
Views
2K
Replies
2
Views
1K
Replies
1
Views
2K
Replies
1
Views
2K
Replies
13
Views
2K
Back
Top