lim as x->0 (tan(x)-x)/(sin2x-2x)
L'Hopitals rule states that if the limit reaches 0/0, you can take the derivative of the top and the bottom until you get the real limit.
The Attempt at a Solution
(sec^2(x)-1)/(2cos2x-2) still 0/0
2sec^2(x)tan(x)/(-4sin(2x)) still 0/0
I have pain stakingly taken the derivative twice more and it simply does not seem to reach any end. All help is very much appreciated!