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I know I have to apply L'hopitals rule to solve this equation, but it seems unsolvable in my eyes. I would be thankful if someone here could spend their time solving this one for me :D

[tex] \frac{ln(cos2x)}{(tanx)^2} [/tex] The variable x is closely 0.

[tex] \frac{ln(cos2x)}{(tanx)^2} [/tex] The variable x is closely 0.

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