L'Hospital's Rule application problem

  • Thread starter Thread starter Sczisnad
  • Start date Start date
  • Tags Tags
    Application
Sczisnad
Messages
9
Reaction score
0

Homework Statement



Use l'Hospital's Rule when necessary (you may not need to use it at all). Find the limit.

lim as x approaches 1 of (x^a-1)/(x^b-1)



Homework Equations





The Attempt at a Solution



Ok well, if you sub in 1 for all the x values you get an indeterminate 0/0 i believe because any power to the base 1 is one. Therefor i apply l'Hospital's Rule.

This gives me (ax^(a-1))/(x^(b)-1)-(bx^(b-1)(x^(a)-1))/((x^(b)-1)^(2))

Still indeterminate... If i take the derivative again the problem gets huge and i feel like i am getting farther away from the answer.
 
Physics news on Phys.org
l'Hopital's rule says to take the derivative of the numerator and divide by the derivative of the denominator. You seem to be taking the derivative of the quotient using the quotient rule. That's not what you want to do.
 
Ah that makes more sense, so all that I would have to do then is find the limit as x approaches 1 of ax^a-1/bx^b-1 which is a/b. so a/b is my answer.
 
Sczisnad said:
Ah that makes more sense, so all that I would have to do then is find the limit as x approaches 1 of ax^a-1/bx^b-1 which is a/b. so a/b is my answer.

That does make more sense.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top