Two particles of masses m and 2m are connected by a light inextensible string, which is
threaded through a fixed smooth ring. If the lighter particle moves uniformly round a
horizontal circle of radius a, while the other particle remains stationary, find the lighter
accel = aw^2
The Attempt at a Solution
Here is my diagram of the problem, I would appreciate it if someone could tell me if this is correct. p is the angle between the 2 ends of string.
Particle is moving uniformly with constant angular speed, w.
T2 - 2mg = 0 by resolving.
So T2 = 2mg.
T1 cos p = mg by resolving.
Using F = m(accel), F = T1 sin p, accel = aw^2
T1 sin p = maw^2
Question 1. Are the tensions equal because if they werent, the string would break?
Question 2. Have I now got to go on and find w? How?
Thanks in advance.
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