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## Homework Statement

Two particles of masses m and 2m are connected by a light inextensible string, which is

threaded through a fixed smooth ring. If the lighter particle moves uniformly round a

horizontal circle of radius a, while the other particle remains stationary, find the lighter

particle's speed.

## Homework Equations

accel = aw^2

## The Attempt at a Solution

Here is my diagram of the problem, I would appreciate it if someone could tell me if this is correct. p is the angle between the 2 ends of string.

http://img166.imageshack.us/img166/7560/question3diagram122lo7.jpg [Broken]

Particle is moving uniformly with constant angular speed, w.

T2 - 2mg = 0 by resolving.

So T2 = 2mg.

T1 cos p = mg by resolving.

Using F = m(accel), F = T1 sin p, accel = aw^2

T1 sin p = maw^2

Question 1. Are the tensions equal because if they werent, the string would break?

Question 2. Have I now got to go on and find w? How?

Thanks in advance.

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