1. The problem statement, all variables and given/known data Two particles of masses m and 2m are connected by a light inextensible string, which is threaded through a fixed smooth ring. If the lighter particle moves uniformly round a horizontal circle of radius a, while the other particle remains stationary, find the lighter particle's speed. 2. Relevant equations accel = aw^2 3. The attempt at a solution Here is my diagram of the problem, I would appreciate it if someone could tell me if this is correct. p is the angle between the 2 ends of string. [Broken] Particle is moving uniformly with constant angular speed, w. T2 - 2mg = 0 by resolving. So T2 = 2mg. T1 cos p = mg by resolving. Using F = m(accel), F = T1 sin p, accel = aw^2 T1 sin p = maw^2 Question 1. Are the tensions equal because if they werent, the string would break? Question 2. Have I now got to go on and find w? How? Thanks in advance.