Likelihood of pairs in a range?

  • Thread starter Thread starter derrend
  • Start date Start date
  • Tags Tags
    Likelihood Range
derrend
Messages
1
Reaction score
0
Running a computer script (included below) I was testing to see how long it would take to match two numbers when selected at random from within a range. To my surprise the percentage of possibilities explored before finding a correct answer decreased as i raised the range.

Is this correct? It seems counter intuitive.--code--:
Code:
#!/usr/bin/python3

import sys
import random

x = int(sys.argv[1])
a = random.randint(0,x)
b = random.randint(0,x)

steps = 1
combos = x**2

while a != b:
	print('[{} {}]'.format(a,b), end=' ')
	a = random.randint(0,x)
	b = random.randint(0,x)
	steps += 1

percent = (steps / combos) * 100
print()
print()

print('[{} ! {}]'.format(a,b), end=' ')
print('equality!'.upper())
print('steps'.upper(), steps)
print('possble combinations = {}'.format(combos))
print('explored {}% possibilitys'.format(percent))
 
Last edited by a moderator:
Mathematics news on Phys.org
Each pair selected has a 1/x probability of being a match. It does not matter what the first pair member is. The second pair member has 1/x probability of matching. The expected number of guesses to get a match is going to be around x.

You are looking at the ratio of x to x2. Of course this decreases as x increases.
 
I'm not familiar with python, but if you want to do some experimentation with random numbers, you probably want to make sure first of all that you are using something better than the default random number method available in the language. Perhaps consider the following and see if that changes the result:

"Warning

The pseudo-random generators of this module should not be used for security purposes. Use os.urandom() or SystemRandom if you require a cryptographically secure pseudo-random number generator.

http://docs.python.org/2/library/random.html"
 
Last edited by a moderator:
jbriggs444 said:
Each pair selected has a 1/x probability of being a match.
It's 1/(x+1), not 1/x. The OP used randint(0,x), which returns a uniformly distributed random integer between 0 and x, inclusive.

The expected number of guesses to get a match is going to be around x.
x+1, to be precise.
hddd123456789 said:
I'm not familiar with python, but if you want to do some experimentation with random numbers, you probably want to make sure first of all that you are using something better than the default random number method available in the language.
Python's random module uses the Mersenne twister with a state size of 19937 bits. That is a very good pseudo random number generator. It is not the bad old rand().
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top