- #1
IntegrateMe
- 217
- 1
lim x tends to 0 of:
[1/(2+x) - 1/2] / x
I simplified the fraction and got:
[x / 2(2+x)] / x
and with further simplification:
x / x(4+2x)
How do I solve this without using L'Hopital's rule?
[1/(2+x) - 1/2] / x
I simplified the fraction and got:
[x / 2(2+x)] / x
and with further simplification:
x / x(4+2x)
How do I solve this without using L'Hopital's rule?