Limit as x Approaches 5: Right = 3, Left = 8, Does Not Exist?

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OrbitalPower

Homework Statement


Says: Let f(x) = x + 3 if x \le5 and
f(x) = 3 if x > 5

And then it asks you to find the limit as x approaches 5 from the left, right, and as x = 5.

I get 3 as x approaches from the right, 8 from the left, and does not exist other words. But he says that's not correct. What am I doing wrong.
 
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Sounds like you reversed the directions.
 
Yah, I did. I reversed it as a wrote it, but I fixed it. Otherwise it is correct?

When x approaches 3 from the left, I should get 8. And from the right, i should get 3. And I don't think it exists at x = 5.

This is for a friend but his webworks says that's wrong.
 
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Yep.
 
cool thanks. I think an email needs to be sent.
 
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