Limit Definition of Derivative

Qube
Gold Member
Messages
461
Reaction score
1

Homework Statement




http://i.minus.com/jbicgHafqNzcvn.png

Homework Equations



The limit definition of a derivative:

[f(x+h)-f(x)]/h as h approaches zero is f'(x)

The Attempt at a Solution



I'm just not understanding the wording of the question. The limit given in the question is indeed equal to g'(x) since it's set up properly and indeed sec(pi) is -1 and subtracting -1 makes it a positive 1.
 
Last edited by a moderator:
Physics news on Phys.org
Qube said:

Homework Statement




http://i.minus.com/jbicgHafqNzcvn.png

Homework Equations



The limit definition of a derivative:

[f(x+h)-f(x)]/h as h approaches zero is f'(x)

The Attempt at a Solution



I'm just not understanding the wording of the question. The limit given in the question is indeed equal to g'(x)

You mean ##g'(\pi)##

since it's set up properly and indeed sec(pi) is -1 and subtracting -1 makes it a positive 1.

So I guess you would mark it True.
 
Last edited by a moderator:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top