Limit Finding for \lim_{x\to 8}\frac{x-8}{x^{\frac{1}{3}}-2} - Homework Solution

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Homework Statement


\lim_{x\to 8}\frac{x-8}{x^{\frac{1}{3}}-2}


Homework Equations


Answer is 12


The Attempt at a Solution


\lim_{x\to 8}\frac{x-8}{x^{\frac{1}{3}}-2}= \lim_{x\to 8}\frac{(x^{\frac{1}{3}}-2)(x^{\frac{2}{3}}+2x^{\frac{1}{3}}+2^2)}{x^{\frac{1}{3}}-2}=\lim_{x\to 8}(x^{\frac{2}{3}}+2x^{\frac{1}{3}}+4)=12
 
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Correct. The latex graphics is not showing everything correctly, though.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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