Limit of Multivariable Function | Squeeze Theorem Example

clandarkfire
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Homework Statement


Hi, I have to evaluate the following limit:
\lim_{(x,y) \to (1,0)}\frac{x*y-y}{(x-1)^2+y^2}


Homework Equations


I'm pretty sure I have to use the squeeze theorem.


The Attempt at a Solution


Well, I'm pretty sure it has something to do with the fact that the top factors like this:
\lim_{(x,y) \to (1,0)}\frac{y(x-1)}{(x-1)^2+y^2}
I'm really new to the squeeze theorem so I don't really know how to use it. I believe I have to find some function comparable to this one that is equal to it or greater than it for all values of x and y and one that is equal or less for all values of x and y. Then I have to prove that both have the same limit, so this function must have it as well.
Oh, and I suspect the limit is 0.
Can someone give me a hand, please?
 
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I would be looking for an argument that the limit doesn't exist.
 
You can simplify the problem via a change of variables: let w = x-1. Then the above limit is equivalent to

\lim_{(w,y)\rightarrow(0,0)} \frac{wy}{w^2 + y^2}

What happens if you let (w,y) \rightarrow (0,0) from different directions?
 
Doh! Thank you. I graphed it and it appeared that it did exist, but I see now I graphed the wrong thing.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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