- #1

username12345

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## Homework Statement

[tex]\mathop {\lim }\limits_{x \to 0 } \frac{1 - cosh(2x)}{{4x^3 + x^2}}[/tex]

## Homework Equations

Product, sum, quotient laws

## The Attempt at a Solution

[tex]\mathop {\lim }\limits_{x \to 0 } \frac{1 - cosh(2x)}{{4x^3 + x^2}} =

\mathop {\lim }\limits_{x \to 0 } \frac{\lim 1 - \lim cosh(2x)}{{\lim 4 + \lim x^3 + \lim x^2}}

=

\mathop {\lim }\limits_{x \to 0 } \frac{1 - \lim cosh(2x)}{{4 + 0 + 0}}

=

\mathop {\lim }\limits_{x \to 0 } \frac{1 - cosh(\lim 2x)}{{4}}

=

\frac{1 - cosh(0)}{{4}}

= \frac{1 - 1}{{4}}

= 0

[/tex]

However the answer is supposed to be 2.

I was sure the denominator should be 4, but not sure how to get 8 in the numerator