Limit of a function at a point (picture included)

maplesyrup23
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I'm trying to find the limit of this function at 0.

I know that for the abs (x) graph, 0 is not differentiable because of abs (h)/h, but I'm not certain about the point on this function.

There is no function given, only the picture.

Thanks in advance!
 

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maplesyrup23 said:
I'm trying to find the limit of this function at 0.

I know that for the abs (x) graph, 0 is not differentiable because of abs (h)/h, but I'm not certain about the point on this function.

There is no function given, only the picture.

Thanks in advance!
It's true that |x| is not differentiable at x = 0. However, limx→0 |x| exists, and is equal to 0.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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