Limit of an exponent when it goes to infinity

RyozKidz
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how this thing works ?

integration of e to the power of (-x) from 0 to infinity

sorry , not good in using the symbols ..^.^ ~
 
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Hi
Do you know what the primitive of e^{-x} is ?
 
First integrate it, then you get [-e-x] from 0 to infinity.

The key is to find the limit as x approaches infinity of (-e-x).

(Hint: Put in a very large negative value for x and see what you get.)
 
sorry ..~ i missed out the negative ..~
now i know already ..~ tq tq ...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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