Limit of ((x^3 + (4x^2)y)/(x^2+2y^2)) as (x,y)->(0,0)

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Homework Statement



Find the limit of ((x^3 + (4x^2)y)/(x^2+2y^2)) as (x,y) -> (0,0)

Homework Equations


The Attempt at a Solution



I am guessing the limit is equal to 0, and I know I have to use

0 < sqrt(x^2 + y^2) < delta where |f(x,y) - L| < epsilon

I just have no idea what to do next
I don't want anyone to give me the answer, just a point in the right direction

Sorry about the formatting, I'm quite lost when it comes to Latex.
 
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Don't worry about the formatting. We can all read that. You used parentheses and everything. Express it in polar coordinates.
 
Sorry it's been a while since I did anything to do with polar, how do I do that?
 
x=r*cos(theta), y=r*sin(theta). You get an r^3 in the numerator and an r^2 in the denominator, yes? Cancel the r^2. Now the limit is r->0.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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