Limit problem, is this right?

  • Thread starter OrbitalPower
  • Start date
  • #1
OrbitalPower

Homework Statement


Says: Let [tex] f(x) = x + 3[/tex] if [tex]x \le5[/tex] and
f(x) = 3 if [tex]x > 5[/tex]

And then it asks you to find the limit as x approaches 5 from the left, right, and as x = 5.

I get 3 as x approaches from the right, 8 from the left, and does not exist other words. But he says that's not correct. What am I doing wrong.
 
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Answers and Replies

  • #2
139
0
Sounds like you reversed the directions.
 
  • #3
OrbitalPower
Yah, I did. I reversed it as a wrote it, but I fixed it. Otherwise it is correct?

When x approaches 3 from the left, I should get 8. And from the right, i should get 3. And I don't think it exists at x = 5.

This is for a friend but his webworks says that's wrong.
 
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  • #5
OrbitalPower
cool thanks. I think an email needs to be sent.
 

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