Limit Problem (L'hospitals rule ) (difference)

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Seiya
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Help please =P I've been doing all the l'hospitals rule problems fine and i did the limit of 1/x-cscx fine... same for otehers but i can't get this one??

lim x->infinity (x-ln[x])

I tried making x = 1/x^-1 and then combining them but that made it so confusing, is that the right approach?? :bugeye:

Any advice appreciated. Thank you!
 
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Your approach works. Just make sure you separately differentiate the fraction in the numerator from the fraction in the denominator.
 

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