Limit problem simplify the root

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Homework Help Overview

The discussion revolves around a limit problem involving algebraic manipulation and simplification of expressions involving square roots. Participants are attempting to understand how to reduce the expression to match a given solution of g/8.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore various algebraic techniques, including multiplying by the conjugate and factoring out common terms. There are discussions about the implications of square roots and limits as variables approach certain values.

Discussion Status

Several participants are actively engaging with the problem, offering suggestions and expressing their own attempts at simplification. While some have made progress, there is no explicit consensus on the final approach or solution, and the discussion remains open-ended.

Contextual Notes

There are references to specific values and conditions, such as the behavior of the expression as c approaches zero or infinity, and the importance of correctly interpreting the square root in relation to the variable x.

StrSpeed
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Homework Statement


[/B]
I feel like I'm missing some theorem which is preventing me from finalizing this problem! It's been driving me nuts I feel like I'm missing something super basic!

Ultimately they've given the solution, g/8, so I know this is how I should try to get the equation to look algebraically. But, no matter how I manipulate it I can't get it to reduce.

I feel like this has to do with √x2 = |x| Which then depending on your value of x will give x, or -x. However, I can't simplify the root into a way which will let me make this jump.
upload_2015-6-5_12-25-51.png


Homework Equations


https://www.desmos.com/calculator/hf8poewlvb

The Attempt at a Solution


https://www.desmos.com/calculator/hf8poewlvb
(link to all my reductions)
 
Last edited:
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Try multiplying numerator and denominator by$$
c\sqrt{\left(\frac{c^2}{g^2}+\frac 1 4\right)}+\frac{c^2}{g}$$
 
The conjugate! How could I forget that.. Thank you! Now I have:

PS. g is not squared I wrote it down wrong.
VhM1czk.jpg


Let me see what more I can do.
 
Alternatively: You can take a common factor out of the expression under the square root to obtain [tex] h(c) = A\sqrt{1 + x} - \frac{c^2}{g}[/tex] where [itex]x < 1[/itex] for sufficiently large [itex]c[/itex]. Hence you may expand the root as a binomial series, [tex] (1 + x)^{\alpha} = 1 + \alpha x + \frac{\alpha(\alpha - 1)}{2!}x^2 + \dots[/tex]
 
Last edited:
Thanks for both of your help! Still working on it, sadly.. I pulled out a C so I'm left with:

https://www.physicsforums.com/file:///C:/Users/Steven/Downloads/CodeCogsEqn.gif
7ScJ3py.gif


Im not entirely sure what I could pull out of the root.
 
Last edited by a moderator:
StrSpeed said:
Thanks for both of your help! Still working on it, sadly.. I pulled out a C so I'm left with:

https://www.physicsforums.com/file:///C:/Users/Steven/Downloads/CodeCogsEqn.gif
7ScJ3py.gif


Im not entirely sure what I could pull out of the root.
Factor out the c you'll have 1/4 * (lim c ->0 1/(sqrt(1/g^2 + 1/4c) + 1/g) and don't forget that 1/4c goes to 0 whenever c -> 0, good luck
 
Last edited by a moderator:
StrSpeed said:
The conjugate! How could I forget that.. Thank you! Now I have:

PS. g is not squared I wrote it down wrong.
VhM1czk.jpg


Let me see what more I can do.
That's good.

##\displaystyle \ \frac14\lim_{c\to\infty}\left(\frac{c^2}{\displaystyle c\sqrt{\left(\frac{c^2}{g^2}+\frac 1 4\right)}+\frac{c^2}{g}}\right)\ ##

One way to deal with rational expressions where some factor →∞ : divide the numerator and denominator by the highest power of that factor.

Divide by c2 in the numerator & denominator.
 
I got it! You guys rock thank you so much! Once I got down to that last x Term I realized that a constant/infinity = 0!

Here is my work through!
od4ZL7X.jpg
 
You should drop the limit sign from the second last row.
 
  • #10
StrSpeed said:
I got it! You guys rock thank you so much! Once I got down to that last x Term I realized that a constant/infinity = 0!

Here is my work through!
upload_2015-6-5_22-57-10.png
At the point highlighted above, simply take the limit and simplify.
 

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