Limit problem, theory very basic question

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Homework Statement




I remember I got it wrong way back in calculus I over this concept.

If I have

lim f(x) = ∞
x→∞

Would it be right to say the limit does not exist? I remember my professor said it was wrong because it does exist and it is infinity.
 
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It doesn't exist on ℝ. However, it does exist on ℝ∪{−∞, +∞}. The latter is usually written as ℝ with a bar over it, but I don't know how to type that.
 
Last edited:
Harrisonized is talking about the "extended real number system". But, in Calculus, you seldom mention that. Typically, in calculus, it is best to think of "lim f(x)= \infty as just meaning "f(x) does not have a limit (for a particular reason)".
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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