Limits and Free Falling Objects

[pippintook]

Use the position function s(t)=-49t^(2) + 200 which gives the height of an object that has fallen from a height of 200 meters. The velocity at time t = a seconds is given by the limit as t goes to a = (s(a) - s(t))/(a-t).
At what velocity will the object impact the ground?


I used V^2 = 2gh and got 62.6 m/s, but am not sure if that is right or if there is another formula I should use.

 

[gabbagabbahey]

The question asks you to find v(a) by computing the limit,

\lim_{t \to a} \frac{s(a)-s(t)}{a-t}

not by plugging it into a kinematics formula.

v(a) is the instantaneous speed of the object at the time t=a. The V you just found is different; it is the speed of the object the instant before it hits the ground, not the speed at t=a. Try your hand at the limit above.