Limits of a Sequence Homework: Find and Prove Answer

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Homework Statement


Let [x] be the greatest integer ≤x. For example [\pi ]=3
and [3]=3
Find lim a_n and prove it.
a) a_n=[\frac{1}{n}]
b) a_n=[\frac{10+n}{2n}]

The Attempt at a Solution


for the first one it will converge to zero.
so can I write \frac{1}{n}< \epsilon
then I can just pick an n large enough to make that work.
for part b, it also looks like it will converge to zero, but a little slower.
so \frac{10+n}{2n}< \epsilon and then solve for n in terms of ε.
Or is there something I am not taking into account with the greatest integer deal?
 
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for the first one:

you are NOT trying to "solve for ε in terms of n", but rather, the other way around. you need to find a (possibly large) value for N so that n > N makes 1/n "small" (less than epsilon). epsilon is arbitrary, but assumed as given.

for the second one, i would note that:

(n+10)/2n = 1/2 + 5/n.

if you find an N such that n > N means 5/n < 1/2,

wouldn't [(n+10)/2n] = 0 for all such n?

it seems to me the floor function "speeds up" the convergence, instead of making it slower.
 
thanks for your help, ok
so on the second one .5+\frac{5}{n} &lt; \epsilon
so then I just pick an n large enough to make it less than epsilon.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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