Line Integral (Flux) Calculation: A(1,4) to B(5,1)

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SUMMARY

The discussion focuses on calculating the line integral (flux) of the function φ(x,y) = 2x + y + 10 along a straight line from point A(1,4) to point B(5,1). The correct parametrization of the line is crucial, with the equation of the line being y = -(3/4)x + 10. The user initially miscalculated the integral, obtaining -9 instead of the correct result of 92. The correct approach involves using the formula for line integrals, specifically integrating the function f(r(t)) multiplied by the magnitude of the derivative of the parametrization.

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jahlin
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Homework Statement


for \varphi(x,y)=2x+y+10 ,calculate the flux line integral...on a straight line from A(1,4) to B(5,1).



Homework Equations





The Attempt at a Solution


I tried to solve it but didnt get the right answer.
first i found the quation of the line which i found to be y=-(3/4)*x
and then i set x=t (parameter) and insert t into the y equation=-(3/4)*t. 1<t<5
dx=dt;dy=-(3/4)dt

and i used the formula for line integral which is \int(2x+y+10)*(dy,-dx)
i subtituted the values for x,y,dx and dt into the above equation and integrated over 5 to 1..
the right answer is 92. i got -9.
 
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By mistake I have removed answer by hgfalling, sorry about that. Here it comes:

The equation of the line is definitely not y=-3x/4: the point (1,4) is on the line!

I'm not sure what your formula for the line integral is at all; is that supposed to be a dot product?
I suggest you parametrize your line correctly as a function r(t); it seems you are on the right track with this. Then

<br /> \intop_S f ds = \intop_a^b f(r(t)) |rsingle-quote(t)| dt <br />
 

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