Line integral of sin cos function

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SUMMARY

The discussion focuses on solving the integral of the function (sin^4(x) + cos^4(x))^.5 dx. Participants explore the transformation of the integral using the substitution u = cos^2(x) and derive the expression 2cos^4(x) - 2cos^2(x) + 1. The importance of including dx in the final expression is emphasized, along with suggestions to utilize the identity (cos(2x) + sin(2x))^2 for further simplification. The conversation highlights common pitfalls in integral calculus and the need for precise notation.

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jbowers9
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Homework Statement



integral (sin^4(x) + cos^4(x))^.5 dx

Homework Equations



sin^2(x) = (1 - cos^2(x))

The Attempt at a Solution



cos^4(x) + {1 - cos^2(x)}^2 = 2cos^4(x) -2cos^2(x) + 1
subst u = cos^2(x)
integral (2u^2 - 2u +1)^.5
 
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hi jbowers9! :smile:

(have a square-root: √ and try using the X2 icon just above the Reply box :wink:)
jbowers9 said:
cos^4(x) + {1 - cos^2(x)}^2 = 2cos^4(x) -2cos^2(x) + 1
subst u = cos^2(x)
integral (2u^2 - 2u +1)^.5

no, you've missed out the dx, which you need to write in the form f(u)du :redface:

(you could try using (cos2x + sin2x)2, but i don't see how to finish that :frown:)
 

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